edaBit-coding-challenges/Strong-Password/code.cpp

/*  Create a function that determines the minimum number of characters needed to make a strong password.
 *  A password is considered strong if it satisfies the following criteria:
 *  Its length is at least 6.
 *  It contains at least one digit.
 *  It contains at least one lowercase English character.
 *  It contains at least one uppercase English character.
 *  It contains at least one special character: !@#$%^&*()-+
 *  Types of characters in a form you can paste into your solution:
 */
bool isSpecial(char c){
	return c == '!' || c == '@' || c == '#' || c == '$' ||\
				 c == '%' || c == '^' || c == '&' || c == '*' ||\
				 c == '(' || c == ')' || c == '-' || c == '+';
}

int strongPassword(std::string password) {
	bool hasDigit = false;
	bool hasLower = false;
	bool minLength = password.size()>=6;
	bool hasUpper = false;
	bool hasSpecial = false;
	for(int i=0;i<password.size();i++){
			if(isdigit(password[i])){hasDigit=true;}
			if(islower(password[i])){hasLower=true;}
			if(isupper(password[i])){hasUpper=true;}
			if(isSpecial(password[i])){hasSpecial=true;}
	}
	// return hasDigit && hasLower && minLength && hasUpper && hasSpecial;
	// return !hasDigit + !hasLower + !minLength + !hasUpper + !hasSpecial;
	// number of criteria have matched
	int criteriaMatch = (hasDigit+hasLower+hasUpper+hasSpecial);
	// number of missing criteria
	int missingCriteria =(!hasDigit+!hasLower+!hasUpper+!hasSpecial);
	// the number of non-contributing characters
	int fluff = password.size() - criteriaMatch;
	// if the number of missing criteria would not add up to six characters
	// we need to add, additional characters.
	int minKneaded = 6 - fluff;
//	int total = fluff + missingCriteria;
//	if(total<6){
	//	return missingCriteria + 6-total;
//	}
	// if they dont have the minimum length how do you calculate extra characters needed
	//return !minLength ? std::max(minKneaded,missingCriteria)
	return !minLength ? 6-password.size()\
		             : missingCriteria;
}