edaBit-coding-challenges/Profitable-Gamble/code.javascript

//  returns true if prob * prize > pay; otherwise return false.
// To illustrate, profitableGamble(0.2, 50, 9) should yield true,
// since the net profit is 1 (0.2 * 50 - 9), and 1 > 0.

function profitableGamble(prob, prize, pay) {
	if ((prob * prize) > pay){return true;}
	else {return false;}
}